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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決
Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決 
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關於瀑布頂底溫度差算法(求物理高手)
Sep 28th 2013, 12:30

Ek(J) =M(kg) * g(m/s^2) * h(m)

= m*9.8*600

= 5880M (J) 此處質量M的單位是kg

= 1400M (cal) 1(cal) = 4.2 (J)

 

H(cal) = m(g)*s(cal/g-°C)*T(°C) 此處質量M的單位是g

= (1000M)*1*T

= 1000MT

H = Ek

1000MT = 1400M

T = 1.4°C

 


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